javascript - Sort array in ascending order while eleminating repeated values -


i'm working on project have array simmilar this

var sortbp = [ 'height58em', 'width480px', 'width768px', 'width959px', 'width767px', 'width767px' ];

i want sort array in ascending order while eleminating repeated values result should 

var sortbp = [ 'height58em', 'width480px', 'width767px', 'width768px', 'width959px' ];

i'm using following function sort array in ascending array how eliminate immediate values ?? (in above case 'width767px')

var sortbp = bparrays.sort(function(a, b) {                     = a.replace(/[a-z]/g, '');                     b = b.replace(/[a-z]/g, '');                     return - b; });

firstly, can't eliminate elements while sorting. have sort array first, remove duplicates. solution using array.prototype.filter , array.prototype.indexof might unsorted array, since array sorted, it's overhead here(takes o(n) each). instead can loop through array , compare element previous one.

function uniq(array) {   var i, l = array.length, result = [];   (i = 0; < l; i++) {     if (result[result.length - 1] != array[i]) {       result.push(array[i]);     }   }   return result; }

this same underscore , prototype's uniq() implemention.

last note: remember work fine sorted array only.


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