bash - How to print a script's source in unix? -


i have custom script in 1 of $path folders. know plaintext python script , not compiled binary. there way print source?

i have tried whereis <scriptname>, doesn't return anything.

$>ls -lrt `echo $path | sed "s/:/\n /g"` | grep <scriptname> lrwxrwxrwx 1 root eng  30 oct 16  2011 <scriptname> -> ../depot/dcs-scripts/bin/<scriptname>

what ../ mean in ../depot/dcs-scripts/bin/<scriptname>?

cat `which scriptname`

usually trick


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