python - Array of 1's in indexed positions -


i have array of indices of minimum values in array.

it looks this:

[[0],  [1],  [2],  [1],  [0]]

(the maximum index 3)

what want array looks this:

[[1, 0, 0]  [0, 1, 0]  [0, 0, 1]  [0, 1, 0]  [1, 0, 0]]

where 1 in column of minimum.

is there easy way in numpy?

use numpy's broadcasting of ==:

>>> minima = np.array([[0], [1], [2], [1], [0]]) >>> minima == arange(minima.max() + 1) array([[ true, false, false],        [false,  true, false],        [false, false,  true],        [false,  true, false],        [ true, false, false]], dtype=bool) >>> (minima == arange(minima.max() + 1)).astype(int) array([[1, 0, 0],        [0, 1, 0],        [0, 0, 1],        [0, 1, 0],        [1, 0, 0]])

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