python - Would decorated function calling another decorator function return normally? -

how control flow work in case of decorators ? there anyway can modify calleedec , make not return caller after getting invoked ? not desired scenario see similar bug wondering if thats possible ? isn't normal functions ?

trying debug issue - hit first pdb not second pdb in scenario below ?

both decorated functions .

@cooldec() def caller():     import pdb;pbd.set_trace()  # hits here     callee()     import pdb;pdb.set_trace() # not here  @calleedec() def callee():     return "okay 

edit:

raising error 1 scenario no error trace .

i can see case callee's decorator in infinite loop or not able job (taking long time) , can happen .

decorated functions plain functions, , have nothing special them regarding program flow.

when in doubt, try expand decorator , see if clearer:

def calleedec(callee_fn):     def wrapped():         print("running callee")         callee_fn()     return wrapped  def callee():     return "okay"  callee = calleedec(callee)  def cooldec(fn):     def wrapped():         print("running caller")         return fn()     return wrapped  @cooldec def caller():     print("caller: start")     callee()     print("caller: end")  caller()  # running caller # caller: start # running callee # caller: end 

to avoid callee hijacking flow , not returning caller function need serious black magic stack. don't think should worry this.

if not hitting second pdb breakpoint, may happening in callee function.