bash - How to remove empty rows from text file -


i have text file [end-of-line-characters in square brackets].

clearly somethings wrong here , want remove empty lines. how can this?

i prefer bash solution, others welcome.

717016|2026493|88650639|agridex|carrier|nr||v/v||nr|||1||nr||nr||nr[cr][lf] 717016|2026493|88650639|agridex|carrier|nr||v/v||nr|||1||nr||nr||nr[cr][lf] 717018|2026494|67685|sulfinyl bis(methane)|carrier|nr||nr||nr|||nr||nr||nr||10% of carrier solution[cr] [cr][lf] [cr][lf] 717019|2026494|57556|1,2-propanediol|carrier|nr||nr||nr|||nr||nr||nr||40% of carrier solution[cr][lf] 717016|2026493|88650639|agridex|carrier|nr||v/v||nr|||1||nr||nr||nr[cr][lf]

this did not work (dont know why..):

sed -i '/^$/d' file.txt

update desired output is

717016|2026493|88650639|agridex|carrier|nr||v/v||nr|||1||nr||nr||nr[cr][lf] 717016|2026493|88650639|agridex|carrier|nr||v/v||nr|||1||nr||nr||nr[cr][lf] 717018|2026494|67685|sulfinyl bis(methane)|carrier|nr||nr||nr|||nr||nr||nr||10% of carrier solution[cr][lf] 717019|2026494|57556|1,2-propanediol|carrier|nr||nr||nr|||nr||nr||nr||40% of carrier solution[cr][lf] 717016|2026493|88650639|agridex|carrier|nr||v/v||nr|||1||nr||nr||nr[cr][lf]

so third line ends [cr][lf] , lines 4 + 5 removed.

use \r represent lf:

sed '/^\r$/d' file

or, run dos2unix on file rid of linefeeds.


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