python 2.7 - How to select following sibling tag with xpath -

i have html file this:

<div id="note">  <a name="overview"></a>  <h3>overview</h3>  <p>some text1...</p>  <a name="description"></a>  <h3>description</h3>  <p>some text2 ...</p> </div>                               ` 

i retrieve paragraph, each header. example, overview: text1 description: text 2 ... want write in python using xpath. thank you.

find h3 tags, iterate on them, , on each step of iteration loop, find next sibling tag p:

import urllib2 lxml import etree  url = "http://www.kb.cert.org/vuls/id/628463" response = urllib2.urlopen(url)  parser = etree.htmlparser() tree = etree.parse(response, parser)  header in tree.iter('h3'):     paragraph = header.xpath('(.//following-sibling::p)[1]')     if paragraph:         print "%s: %s" % (header.text, paragraph[0].text) 

prints:

overview: ruby on rails 3.0 , 2.3 json parser contain vulnerability may result in arbitrary code execution. description: lawrence pit of mirror42 discovering vulnerability. impact: lawrence pit of mirror42 discovering vulnerability. solution: lawrence pit of mirror42 discovering vulnerability. vendor information : lawrence pit of mirror42 discovering vulnerability. cvss metrics : lawrence pit of mirror42 discovering vulnerability. references: lawrence pit of mirror42 discovering vulnerability. credit: lawrence pit of mirror42 discovering vulnerability. feedback: if have feedback, comments, or additional information vulnerability, please send  subscribe updates: receive security alerts, tips, , other updates.