c# - Detect the word after a regex -

i have long text , part of text is

hello , john how (1)are (are/is) you?

i used detect (1).

string optionpattern = "[\\(]+[0-9]+[\\)]"; regex reg = new regex(optionpattern); 

but got stuck here @ continue on how detect after (1) find are.

full code ( falsetru bringing me far) :

string optionpattern = @"(?<=\(\d+\))\w+"; regex reg = new regex(optionpattern);  string[] passage = reg.split(lstquestion.questioncontent); foreach (string s in passage) {     textblock tblock = new textblock();     tblock.fontsize = 19;     tblock.text = s;     tblock.textwrapping = textwrapping.wrapwithoverflow;     wrappanel1.children.add(tblock); } 

i assume if split this, remove words after (0-9), when run it removes word after () in last detection.

as can see word after (7) gone rest not.

how detect are after (1)?
possible replace word after (1) textbox too?

use positive lookbehind lookup ((?<=\(\d+\))\w+):

string text = "hello , john how (1)are (are/is) you?"; string optionpattern = @"(?<=\(\d+\))\w+"; regex reg = new regex(optionpattern); console.writeline(reg.match(text)); 

prints are

alternative: capture group (\w+)

string text = "hello , john how (1)are (are/is) you?"; string optionpattern = @"\(\d+\)(\w+)"; regex reg = new regex(optionpattern); console.writeline(reg.match(text).groups[1]); 

btw, using @"..", don't need escape \.

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update

instead of using .split(), .replace():

string text = "hello , john how (1)are (are/is) you?"; string optionpattern = @"(?<=\(\d+\))\s*\w+"; regex reg = new regex(optionpattern); console.writeline(reg.replace(text, "")); 

alternative:

string text = "hello , john how (1)are (are/is) you?"; string optionpattern = @"(\(\d+\))\s*\w+"; regex reg = new regex(optionpattern); console.writeline(reg.replace(text, @"$1")); 

prints

hello , john how (1) (are/is) you?