c# - Regex finding any characters in between ( ) -

i have long text , in text there many ( hello , hi ) or (hello,hi) , have take space account . how detect them in long text , retrieve hello , hi word , add list text? use regex :

   string helpingwordpattern = "(?<=\\()(.*?)(?<=\\))";    regex regexhelpingword = new regex(helpingwordpattern);          foreach (match m in regexhelpingword.matches(lstquestion.questioncontent))        {            //  removing "," , store helping word list            string str = m.tostring();            if (str.contains(","))            {                 string[] strwords = str.split(','); // contain ) word , e.g. ( whole) )                  if(strwords.contains(")"))                 {                    strwords.replace(")", ""); // try remove them. error here cos can't use array replace.                }                     foreach (string words in strwords)                    {                        options.add(words);                    }             }        } 

i google , search correct regex , regex use suppose remove ) doesn't .

you can use regex pattern:

(?<=[\(,])(.*?)(?=[\),]) (?<=[\(,])(\d*?)(?=[\),])  // except number 

break up:

(?<=[\(,])  = positive behind, looks `(`or `,`  (.*?)       = looks thing except new line, lazy(matches less possible)   (?=[\),])   = positive ahead, looks `)` or `,` after `hello` or `hi` etc. 

demo

edit

you can try sample code achievement: (untested)

list<string> lst = new list<string>(); matchcollection mcoll = regex.matches(samplestr,@"(?<=[\(,])(.*?)(?=[\),])")  foreach(match m in mcoll) {     lst.add(m.tostring());     debug.print(m.tostring());   // optional, check in output window. }