Can a function be passed as an argument in PHP? -

i wanting pass functon argument using php, in equivalent way jquery allows passing of functions.

jquery:

$("#foo").bind("click", function(){      alert("hello world!"); }); 

so, tried using php:

$arg1 = "hello"; $arg2 = function($name){echo $name;};  function call_me($func_arg1="", $func_arg2=""){      echo $func_arg1." ".$func_arg2("world!"); }  call_me($arg1, $arg2); 

... "world!hello" returned .... why return outcome backwards ?

ok, found answer. because trying echo echo! changed that:

$arg2 = function($name){return $name;}; 

this output "hello world!" expected.